Generating Phone Number in Java

Problem:

Write an application that creates and prints a random phone number of the form xxx-xxx-xxxx. Include the dashed in the output. Do not let the first three digits contain an 8 or 9. And make sure that the second set of three digits is not greater than 742 (i.e. ≤ 742). Hint: Think through the easiest way to construct he phone number. Each digit does not have to be determined separately.

Output:

016-326-5981

Solution:

import java.util.Random;
public class Problem4 {

   public static void main(String args[])
   {
     Random generator = new Random();


     // Generate 3 random numbers between 0 & 7 for the first part of the phone number
  int one = generator.nextInt(8);
  int two = generator.nextInt(8);
  int three = generator.nextInt(8);
  int fourtosix = generator.nextInt(743);
  int seventoten = generator.nextInt(10000);
  String sOne = "" + (one);
  String sTwo = "" + (two);
  String sThree = "" + (three);
  String sFourtosix = "";
  String sSeventoten = "";
  if (fourtosix >= 0 && fourtosix < 10)
   sFourtosix = "00" + (fourtosix);
   else
    if(fourtosix < 100)
     sFourtosix = "0" + (fourtosix);
    else
     sFourtosix = "" + (fourtosix);
     
  if (seventoten >= 0 && seventoten < 10)
   sSeventoten = "000" + (seventoten);
   else
    if(seventoten < 100)
     sSeventoten = "00" + (seventoten);
    else
     if(seventoten < 1000)
      sSeventoten = "0" + (seventoten);
      else
       sSeventoten = "" + (seventoten);  
 

  //Print the phonenumber with this format xxx-xxx-xxxx
  System.out.printf(sOne + sTwo + sThree +"-" +sFourtosix + "-" + sSeventoten);
   }


}