Problem:
Given an int n, return the absolute difference between n and 21, except return double the absolute difference if n is over 21.
diff21(19) → 2
diff21(10) → 11
diff21(21) → 0
Solution:
public int diff21(int n) {
int sum = Math.abs(21 - n);
if (n > 21)
return 2 * sum;
else
return sum;
}

public int diff21(int n) {
ReplyDeletereturn (n <= 21)? (21 - n) : (2 * n - 42);
}
can u tell me what the algorithm set would be
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