Convert this C code into Assembly (MIPS)

Problem: Hello there, I am an old guy who understands only low level languages and my son showed me this C code: f = (g + h) - (i + j);
Would you help convert this to assembly?

Solution:
#Remember that arithmetic operations can have at most three operands.
sum x, g, h #Puts the addition of g and h in x
sum y, i, j #Puts the addition of i and j in y
sub f, x, y #Puts the subtraction of x and y into f


10 comments :

  1. Indeed it was a difficult task to convert that algebraic sum into assemble but kudoos to you that you did it very efficiently and helped that guy.

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  4. This is a useful programming exercise for understanding how C code maps to lower-level MIPS assembly instructions. Working through the conversion step by step can help learners understand registers, memory operations, and program flow more clearly. For a quick choice between two approaches while solving a problem, you can also use Virtueller Münzwurf as a simple decision-making tool.

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