Java > String-1 > withoutX2 (CodingBat Solution)

Problem:

Given a string, if one or both of the first 2 chars is 'x', return the string without those 'x' chars, and otherwise return the string unchanged. This is a little harder than it looks.

withoutX2("xHi") → "Hi"
withoutX2("Hxi") → "Hi"
withoutX2("Hi") → "Hi"


Solution:

public String withoutX2(String str) {
  String temp = "";

  for (int i = 0; i < str.length(); i++) {
    if (i == 0 && str.charAt(i) != 'x')
      temp += str.charAt(i);
    else if (i == 1 && str.charAt(i) != 'x')
      temp += str.charAt(i);
    else if (i > 1)
      temp += str.charAt(i);
  }
  
  return temp;
}


18 comments :

  1. OMG another solution with a loop when is not supposed to? GG!

    ReplyDelete
  2. public String withoutX2(String str) {
    String r=str;
    if (str.length()>1 && str.charAt(1)=='x')
    r=str.substring(0,1)+str.substring(2);
    if (str.length()>0 && str.charAt(0)=='x')
    r=r.substring(1);
    return r;
    }

    ReplyDelete
  3. public String withoutX2(String str){
    if(str.length() > 1 && str.charAt(1) == 'x')
    str = str.substring(0, 1) + str.substring(2);
    if(str.length() > 0 && str.charAt(0) == 'x')
    str = str.substring(1);
    return str;
    }

    ReplyDelete
    Replies
    1. This is likely the solution the designer of the exercises wished to see. No loops, no use of StringBuilder, one return statement.

      Delete
  4. Here is a shorter solution:

    public String withoutX2(String str)
    {
    String word = "";
    for(int i=0; i<str.length(); i++)
    {
    if((i==0||i==1) && str.charAt(i)=='x')
    continue;
    word += str.charAt(i);
    }
    return word;
    }

    ReplyDelete
  5. // if want to know how not to solve it correctly



    public String withoutX2(String str) {

    int i=0;
    char ch ;
    String temp ="";

    for( i=0;i<str.length();i++){
    ch = str.charAt(i);
    if( ch == 'x'){
    if(i<2){
    ch ='_';
    }
    }
    temp += ch;
    }

    return temp.replace("_","");

    }

    ReplyDelete
  6. public String withoutX2(String str) {
    StringBuilder str2 = new StringBuilder();
    for (int i = 0; i < str.length(); i++) {
    if (str.charAt(i) == 'x' && i < 2)
    continue;
    str2.append(str.charAt(i));
    }
    return str2.toString();
    }

    ReplyDelete
  7. public String withoutX2(String str) {
    if(str.length() == 0) {
    return "";
    }
    if(str.length() == 1 && str.charAt(0) == 'x'){
    return "";
    }
    String twoFirstLetter = str.substring(0, 2);

    int indexFirstX = twoFirstLetter.charAt(0) == 'x' ? 0 : -1;
    int indexSecondX = twoFirstLetter.charAt(1) == 'x' ? 1 : -1;

    if(indexFirstX != -1 && indexSecondX != -1){
    return str.substring(2);
    }
    if(indexFirstX != -1 && indexSecondX == -1){
    return str.substring(1);
    }
    if(indexFirstX == -1 && indexSecondX == 1){
    return twoFirstLetter.charAt(0) + str.substring(2);
    }
    return str;
    }

    ReplyDelete
  8. public String withoutX2(String str) {
    String result = "";
    if (str.equals("x") || str.equals("xx") || str.equals(result)) {
    return result;
    }
    if (str.length() > 1) {
    String tmp = str.substring(0, 2);
    tmp = tmp.replaceAll("x", "");
    result = tmp + str.substring(2);
    }
    return result;
    }

    ReplyDelete
  9. int count = 0;
    for (int i = 0; i < str.length()-1; i++ ){
    if (str.substring(i,i+2).equals("hi"))
    count++;
    }
    return count;

    ReplyDelete
  10. int count = 0;
    for (int i = 0; i < str.length()-1; i++ ){
    if (str.substring(i,i+2).equals("hi"))
    count++;
    }
    return count;

    ReplyDelete
  11. int count = 0;
    for (int i = 0; i < str.length()-1; i++ ){
    if (str.substring(i,i+2).equals("hi"))
    count++;
    }
    return count;

    ReplyDelete
  12. public String withoutX2(String str) {
    String withoutX= "";
    if (str.length() >2)
    {
    String firstX = str.substring(0,1);
    String secondX = str.substring(1,2);
    String lastX = str.substring(2);
    if(!firstX.equals("x"))
    {
    withoutX+=firstX;
    }
    if(!secondX.equals("x"))
    {
    withoutX+=secondX;
    }

    withoutX+=lastX;
    }
    else if (str.length()==1)
    {
    if (!str.substring(0,1).equals("x"))
    {
    withoutX+=str.substring(0,1);
    }
    }
    else if (str.length()==2)
    {
    if (!str.substring(0,1).equals("x"))
    {
    withoutX+=str.substring(0,1);
    }
    if (!str.substring(1,2).equals("x"))
    {
    withoutX+=str.substring(1);
    }
    }

    return withoutX;
    }

    ReplyDelete
  13. if(str.equals("x") || str.isEmpty()){
    return "";
    }
    String firstTwo = str.substring(0,2);
    String replacement = firstTwo.replaceAll("x","");

    if(firstTwo.contains("x")){
    return replacement + str.substring(2);

    }
    return str;

    ReplyDelete
  14. public String withoutX2(String str) {
    if(str.equals("x") || str.isEmpty()){
    return "";
    }
    if(str.substring(0, 2).contains("x")){
    return str.substring(0, 2).replaceAll("x","") + str.substring(2);
    }
    return str;
    }

    ReplyDelete
  15. public String withoutX2(String str) {
    if(str.equals("x") || str.isEmpty()){
    return "";
    }
    if(str.substring(0, 2).contains("x")){
    return str.substring(0, 2).replaceAll("x","") + str.substring(2);
    }
    return str;
    }

    ReplyDelete
  16. public String withoutX2(String str) {
    if(str.equals("x") || str.isEmpty()){
    return "";
    }
    if(str.substring(0, 2).contains("x")){
    return str.substring(0, 2).replaceAll("x","") + str.substring(2);
    }
    return str;
    }

    ReplyDelete

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