Java > Warmup-1 > max1020 (CodingBat Solution)

Problem:

Given 2 positive int values, return the larger value that is in the range 10..20 inclusive, or return 0 if neither is in that range.

max1020(11, 19) → 19
max1020(19, 11) → 19
max1020(11, 9) → 11

Solution:

public int max1020(int a, int b) {
int OUTPUT =0;
if (a >= 10 && b <=20)
{
 if (a > b )OUTPUT = a;
   else if (b > a) OUTPUT = b;
  
   }
  
    // (10 <= a <= 20)  and   (b > 20 or b < 10)  return a;
    //( a > 20 or a < 20) and (10<=b <=20 return b;
   
   if ( (10 <= a && a <=20) && (b>20 || b < 10) )
        OUTPUT = a;
   if ( ( a > 20 || a <10) && (10 <=b && b <= 20) )
        OUTPUT = b;
       
        return OUTPUT;
         }