Reversing and sorting an array in Java

Problem:

Write a program that reads 10 values of integers from the user store them in an array of integers.
a. Then print the reverse of this array.
Example:

1 6 3 4 2 9 8 10 5 7

Reverse: 7 5 10 8 9 2 4 3 6 1
b.The program writes the array in increasing order. (Using for loops).

Increasing order: 1 2 3 4 5 6 7 8 9 10

Output:

Not applicable.

Solution:

import java.util.Scanner;

public class Prob2
{
	public static void main(String[] args)
	{
		Scanner scan = new Scanner(System.in);
		System.out.println("Please enter " + 10 + " numbers: ");
		int[] list = new int[10];
		
		for(int i=0; i<10; i++)
		{
			list[i] = scan.nextInt();
		} 
		
        System.out.println("The array in reverse is: ");
        for(int i=9; i>=0; i--)
		{
			System.out.print(list[i] + " ");
		}
		
		System.out.println();
		System.out.println("The array in increassing order is: ");
		for(int i=0;i<list.length;i++)
		{
			int temp = 0;
			for(int j=0;j<list.length-1;j++)
			{
				if(list[j]>list[j+1])
				{
					temp = list[j];
					list[j] = list[j+1];
					list[j+1] = temp;
				}
			}
		}
   		for(int i=0; i<list.length; i++)
		{
			System.out.print(list[i] + " ");
		}         
                
		
	}
	
	
	
}