**Problem:**

It is well known that if the square root of a natural number is not an integer, then it is irrational. The decimal expansion of such square roots is infinite without any repeating pattern at all.

The square root of two is 1.41421356237309504880..., and the digital sum of the first one hundred decimal digits is 475.

For the first one hundred natural numbers, find the total of the digital sums of the first one hundred decimal digits for all the irrational square roots.

The square root of two is 1.41421356237309504880..., and the digital sum of the first one hundred decimal digits is 475.

For the first one hundred natural numbers, find the total of the digital sums of the first one hundred decimal digits for all the irrational square roots.

**Solution:**

443839

**Code:**

The solution may include methods that will be found here: Library.java .

The solution may include methods that will be found here: Library.java .

public interface EulerSolution{

public String run();

}

/*

* Solution to Project Euler problem 30

* By Nayuki Minase

*

* http://nayuki.eigenstate.org/page/project-euler-solutions

* https://github.com/nayuki/Project-Euler-solutions

*/

public final class p030 implements EulerSolution {

public static void main(String[] args) {

System.out.println(new p030().run());

}

public String run() {

// As stated in the problem, 1 = 1^5 is excluded.

// If a number has at least n >= 7 digits, then even if every digit is 9,

// n * 9^5 is still less than the number (which is at least 10^n).

int sum = 0;

for (int i = 2; i < 1000000; i++) {

if (i == fifthPowerDigitSum(i))

sum += i;

}

return Integer.toString(sum);

}

private static int fifthPowerDigitSum(int x) {

int sum = 0;

while (x != 0) {

int y = x % 10;

sum += y * y * y * y * y;

x /= 10;

}

return sum;

}

}

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