## Problem:

As we all know the equation x2=-1 has no solutions for real x.
If we however introduce the imaginary number i this equation has two solutions: x=i and x=-i.
If we go a step further the equation (x-3)2=-4 has two complex solutions: x=3+2i and x=3-2i.
x=3+2i and x=3-2i are called each others' complex conjugate.
Numbers of the form a+bi are called complex numbers.
In general a+bi and a[−]bi are each other's complex conjugate.

A Gaussian Integer is a complex number a+bi such that both a and b are integers.
The regular integers are also Gaussian integers (with b=0).
To distinguish them from Gaussian integers with b [≠] 0 we call such integers "rational integers."
A Gaussian integer is called a divisor of a rational integer n if the result is also a Gaussian integer.
If for example we divide 5 by 1+2i we can simplify in the following manner:
Multiply numerator and denominator by the complex conjugate of 1+2i: 1[−]2i.
The result is .
So 1+2i is a divisor of 5.
Note that 1+i is not a divisor of 5 because .
Note also that if the Gaussian Integer (a+bi) is a divisor of a rational integer n, then its complex conjugate (a[−]bi) is also a divisor of n.

In fact, 5 has six divisors such that the real part is positive: {1, 1 + 2i, 1 [−] 2i, 2 + i, 2 [−] i, 5}.
The following is a table of all of the divisors for the first five positive rational integers:

n Gaussian integer divisors
with positive real part Sum s(n) of
these divisors
1 1 1
2 1, 1+i, 1-i, 2 5
3 1, 3 4
4 1, 1+i, 1-i, 2, 2+2i, 2-2i,4 13
5 1, 1+2i, 1-2i, 2+i, 2-i, 5 12

For divisors with positive real parts, then, we have: .

For 1 [≤] n [≤] 105, [∑] s(n)=17924657155.

What is [∑] s(n) for 1 [≤] n [≤] 108?

6857

## Code:The solution may include methods that will be found here: Library.java .

public interface EulerSolution{public String run();}
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