## Problem:

Some positive integers n have the property that the sum [ n + reverse(n) ] consists entirely of odd (decimal) digits. For instance, 36 + 63 = 99 and 409 + 904 = 1313. We will call such numbers reversible; so 36, 63, 409, and 904 are reversible. Leading zeroes are not allowed in either n or reverse(n).

There are 120 reversible numbers below one-thousand.

How many reversible numbers are there below one-billion (109)?

1533776805

## Code:The solution may include methods that will be found here: Library.java .

public interface EulerSolution{public String run();}
/*  * Solution to Project Euler problem 45 * By Nayuki Minase *  * http://nayuki.eigenstate.org/page/project-euler-solutions * https://github.com/nayuki/Project-Euler-solutions */public final class p045 implements EulerSolution {		public static void main(String[] args) {		System.out.println(new p045().run());	}			public String run() {		int i = 286;		int j = 166;		int k = 144;		while (true) {			long triangle = (long)i * (i + 1) / 2;			long pentagon = (long)j * (j * 3 - 1) / 2;			long hexagon  = (long)k * (k * 2 - 1);			long min = Math.min(Math.min(triangle, pentagon), hexagon);			if (min == triangle && min == pentagon && min == hexagon)				return Long.toString(min);			if (min == triangle) i++;			if (min == pentagon) j++;			if (min == hexagon ) k++;		}	}	}