##
**Problem:**

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

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**Solution:**

233168

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**Code:**

The solution may include methods that will be found here: Library.java .

The solution may include methods that will be found here: Library.java .

public interface EulerSolution{ public String run(); }

/* * Solution to Project Euler problem 1 * By Nayuki Minase * * http://nayuki.eigenstate.org/page/project-euler-solutions * https://github.com/nayuki/Project-Euler-solutions */ public final class p001 implements EulerSolution { public static void main(String[] args) { System.out.println(new p001().run()); } public String run() { int sum = 0; for (int i = 0; i < 1000; i++) { if (i % 3 == 0 || i % 5 == 0) sum += i; } return Integer.toString(sum); } }

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