Java > AP-1 > scoresAverage (CodingBat Solution)

Problem:

Given an array of scores, compute the int average of the first half and the second half, and return whichever is larger. We'll say that the second half begins at index length/2. The array length will be at least 2. To practice decomposition, write a separate helper method
int average(int[] scores, int start, int end) { which computes the average of the elements between indexes start..end. Call your helper method twice to implement scoresAverage(). Write your helper method after your scoresAverage() method in the JavaBat text area. Normally you would compute averages with doubles, but here we use ints so the expected results are exact.

scoresAverage({2, 2, 4, 4}) → 4
scoresAverage({4, 4, 4, 2, 2, 2}) → 4
scoresAverage({3, 4, 5, 1, 2, 3}) → 4

Solution:

public int scoresAverage(int[] scores) {
int avg1 = average(scores, 0, scores.length/2);
int avg2 = average(scores, scores.length/2, scores.length);

return Math.max(avg1,avg2);

}

public int average(int[] scores, int start, int end) {
int sum = 0;
for (int i = start; i < end; i++) {
sum += scores[i];
}
return sum / (end-start);
}


No comments :

Post a Comment

Follow Me

If you like our content, feel free to follow me to stay updated.

Subscribe

Enter your email address:

We hate spam as much as you do.

Upload Material

Got an exam, project, tutorial video, exercise, solutions, unsolved problem, question, solution manual? We are open to any coding material. Why not upload?

Upload

Copyright © 2012 - 2014 Java Problems  --  About  --  Attribution  --  Privacy Policy  --  Terms of Use  --  Contact