Java > AP-1 > copyEvens (CodingBat Solution)

Problem:

Given an array of positive ints, return a new array of length "count" containing the first even numbers from the original array. The original array will contain at least "count" even numbers.

copyEvens({3, 2, 4, 5, 8}, 2) → {2, 4}
copyEvens({3, 2, 4, 5, 8}, 3) → {2, 4, 8}
copyEvens({6, 1, 2, 4, 5, 8}, 3) → {6, 2, 4}


Solution:

public int[] copyEvens(int[] nums, int count) {
  int ctr = 0;
  int[] array = new int[count];
  for (int i = 0; i < nums.length; i++) {
    if (nums[i] % 2 == 0) {
      array[ctr] = nums[i];
      ctr++;
    }
      if (ctr == count)
        return array;
  }
  return nums;
}


3 comments :

  1. public int[] copyEvens(int[] nums, int count) {
    int[] result = new int[count];
    int counter = 0;
    for(int i=0; i<nums.length && counter<count; i++)
    {
    if(nums[i]%2==0)
    {
    result[counter]=nums[i];
    counter++;
    }
    }
    return result;
    }

    ReplyDelete
  2. int index=0;
    int[] arr = new int[count];
    for(int n : nums){
    if(n%2==0 && index<count) {
    arr[index]=n;
    index++;
    }
    }return arr;

    ReplyDelete
  3. int[] filteredArray = Arrays.stream(nums).filter(n -> n%2==0).toArray();
    return Arrays.copyOfRange(filteredArray, 0 ,count);

    ReplyDelete

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