Checking Weather Your Name is Listed or Not in Java

Problem:

Write a program that reads an integer N followed by N lists of strings. Each list ends with the string “xyz”. If your first name appears in list K (1 <= K <= N), and K is the smallest such value, then your program prints “My name is in list K!” Otherwise, it prints “My name is not listed. Please add it somewhere.”

Output:

3
Mike
Gregory
Henning
John
xyz
George
Faisal
xyz
Mathew
Faisal
Rolf
xyz
My name is in list 2

Solution:

import java.util.Scanner;
 
public class lauprob2
{
 public static void main (String[] args)
 
 {
  Scanner scan = new Scanner(System.in);
  
  String str = "e";
  
  int input = scan.nextInt();
  
  /*We're making an array of n integers,
   with n being the number of lists we're going
   to read from the screen*/
   int[] name_appearance = new int[input];
  //Note: the value of all 3 integer variables of this array is zero by default 

  //We're going to loop over each entered list to keep track
  //of where my name is appearing
  for (int count = 0; count < input; count++)
   
  {
   //We just need a random initial value for the String variable that we
   //will be using to check the scanned string 
   str = "e";
   
   //In this inner loop, we're going to loop over each scanned string
   //from the same list to check if my name is there.
   //Note: the condition will stop the loop when we reach our end marker=xyz
   for (int index = 0; !(str.equals("xyz"));index++)
    
   {
    str = scan.nextLine();
    
    //If we found out that my name is equal to the entered String
   //in list number n, we're going to make
    if (str.equalsIgnoreCase("george") && index < input)
     
     //In this step, we're going to make the array element (list number) that
    //has my name be equal to well, the actual list number
    name_appearance[count] = count+1;
    
    //for example, if the second list has my name, then what we're really doing here
    //is having count=1 and making name_appearance[1]=1+1=2
    //If the name was at the first list (i.e., at our first try without increasing count)
    //then the variables would be count=0 and name_apperance[0]=1
 
   }
   
  }
  
  //We're going to go through each array element to check which element has a value
  //other than zero; this is because we changed the array element value of the list that
  //has my name in the loops above. Kinna sounds complicated and weird, but this is     
  // just one way of solving this problem so don't get freaked out over not
  // wanting to ever do this code again :P
  
  for (int NameList : name_appearance)
   
   if (NameList != 0)
    
    System.out.println("My name is in list" + NameList);
  
 }
 
}