Java > Warmup-2 > last2 (CodingBat Solution)

Problem:

Given a string, return the count of the number of times that a substring length 2 appears in the string and also as the last 2 chars of the string, so "hixxxhi" yields 1 (we won't count the end substring).

last2("hixxhi") → 1
last2("xaxxaxaxx") → 1
last2("axxxaaxx") → 2


Solution:

public int last2(String str) {
  if (str.length() < 2) return 0;
 
  String end = str.substring(str.length()-2);

  int count = 0;
  
  for (int i=0; i<str.length()-2; i++) {
    String sub = str.substring(i, i+2);
    if (sub.equals(end)) {
      count++;
    }
  }

  return count;

}

2 comments:

  1. UnknownApril 14, 2020 at 3:21 AM

    public int last2(String str) {
    int len = str.length();
    int count = 0;

    if(len <= 2){
    return 0;
    }

    for(int i = 0; i < len-2; i++){
    String last = str.substring(len-2);
    if(str.substring(i, i+2).equals(last)){
    count++;
    }
    }
    return count;
    }

    ReplyDelete
  2. SardorbekDecember 1, 2021 at 4:01 AM

    public int last2(String str) {
    int count=0;
    int len=str.length();
    for (int i = 0; i <len-2 ; i++) {
    if(str.substring(len-2).compareTo(str.substring(i,i+2))==0){
    count++;
    }


    }
    return count;

    }

    ReplyDelete