Java > Warmup-1 > nearHundred (CodingBat Solution)

Problem:

Given an int n, return true if it is within 10 of 100 or 200. Note: Math.abs(num) computes the absolute value of a number.

nearHundred(93) → true
nearHundred(90) → true
nearHundred(89) → false


Solution:

public boolean nearHundred(int n) {
  int sum1 = Math.abs(n - 100);
  int sum2 = Math.abs(n - 200);
  
  if (sum1 <= 10 || sum2 <= 10)
    return true;
  else
    return false;
}

3 comments:

  1. AnonymousSeptember 13, 2020 at 3:04 PM

    public boolean nearHundred(int n) {
    return (90 <= n && n <= 110) || (190 <= n && n <= 210);
    }

    ReplyDelete
  2. FiddaDecember 20, 2021 at 2:19 AM

    return n>=90&&n<=110||n>=190&&n<=210;

    ReplyDelete
  3. Jayadeep VarmaAugust 18, 2023 at 6:36 AM

    for both sum1 and sum2 the value should be less than or equal to 10 so the code will be as
    if(sum1<=10 || sum2<=10)

    ReplyDelete