Java &gt; String-3 &gt; sumNumbers (CodingBat Solution)

Problem:

Given a string, return the sum of the numbers appearing in the string, ignoring all other characters. A number is a series of 1 or more digit chars in a row. (Note: Character.isDigit(char) tests if a char is one of the chars '0', '1', .. '9'. Integer.parseInt(string) converts a string to an int.)

sumNumbers("abc123xyz") → 123
sumNumbers("aa11b33") → 44
sumNumbers("7 11") → 18

Solution:

public int sumNumbers(String str) {
  int len = str.length();
  int sum = 0;
  String tmp = "";
  
  for (int i = 0; i < len; i++) {
    if (Character.isDigit(str.charAt(i))) {
      if (i < len-1 && Character.isDigit(str.charAt(i+1))) {
        tmp += str.charAt(i);
      }
      else {
        tmp += str.charAt(i);
        sum += Integer.parseInt(tmp);
        tmp = "";
      }
        
    }
  }
  
  return sum;
}

4 comments:

AnonymousSeptember 14, 2017 at 10:54 AM
public int sumDigits(String str) {
int sum = 0;
for(int i = 0; i<str.length(); i++){
if (Character.isDigit(str.charAt(i)))
sum += Integer.parseInt(str.substring(i,i+1));
}
return sum;
}
lakohotJune 18, 2019 at 2:05 AM
public int sumNumbers(String str) {
str = str + " ";
int count = 0;
String temp = "";

for (int i = 0; i < str.length(); i++) {
if (Character.isDigit(str.charAt(i))) {
temp += str.charAt(i);
}
else if (!(temp.isEmpty())) {
count += Integer.parseInt(temp);
temp = "";
}
}
return count;
}
UnknownJuly 23, 2019 at 2:01 AM
public int sumNumbers(String str) {
if(str.length()<1)return 0;
int res=0;
int tmp=0;
for(int i=0; i<str.length(); i++) {
if(Character.isDigit(str.charAt(i))) {
tmp*=10;
tmp+= Integer.parseInt(str.substring(i, i+1));
}
if(i==str.length()-1 || !Character.isDigit(str.charAt(i+1))) {
res+=tmp;
tmp=0;
}
}
return res;
}
AnonymousSeptember 13, 2020 at 4:01 PM
public int sumNumbers(String str) {
int sum=0, num=0;
for (final char c : (str.concat(".")).toCharArray())
if (Character.isDigit(c))
num = num * 10 + (c - '0');
else {
sum += num;
num = 0;
}
return sum;
}