Java > String-2 > repeatFront (CodingBat Solution)

Problem:

Given a string and an int n, return a string made of the first n characters of the string, followed by the first n-1 characters of the string, and so on. You may assume that n is between 0 and the length of the string, inclusive (i.e. n >= 0 and n <= str.length()).

repeatFront("Chocolate", 4) → "ChocChoChC"
repeatFront("Chocolate", 3) → "ChoChC"
repeatFront("Ice Cream", 2) → "IcI"


Solution:

public String repeatFront(String str, int n) {
  int len = str.length();
  String newWord = "";
  
  for (int i = n; n > 0; n--){
    newWord += str.substring(0,n);
  }
  return newWord;
}

20 comments:

  1. AnonymousFebruary 17, 2017 at 6:10 PM

    String result = "";

    for( ; n >= 0; n-- ) {
    result += str.substring(0, n);
    }
    return result;

    ReplyDelete
  2. AnonymousDecember 15, 2017 at 1:18 AM

    String s="";
    for(int i=0;i<n;)
    {
    s = s + str.substring(i,n);
    n--;
    }
    return s;

    ReplyDelete
  3. Navid AfzalMarch 9, 2018 at 12:16 PM

    String result = "";

    while (n > 0) {
    result = result + str.substring(0,n);
    n--;
    }

    return result;

    ReplyDelete
  4. AnonymousJune 13, 2018 at 9:54 AM

    public String repeatFront(String str, int n) {
    String result="";
    int a =n;
    for(int i=0;i<a;i++){
    result+=str.substring(0,n);
    n--;
    }
    return result;
    }

    ReplyDelete
  5. JuanAndresAugust 6, 2019 at 5:44 PM

    public String repeatFront(String str, int n) {
    String c= "";

    for(int i=n;i>=0;i--) {

    c+=str.substring(0,i);
    }
    return c;

    }

    ReplyDelete
  6. AbudéSeptember 1, 2019 at 11:56 PM

    public String repeatFront(String str, int n) {
    String result = "";
    if ( n == 0 || n <= str.length() ){
    for ( int i = n; i > 0 ; i--){
    result += str.substring(0,i);
    }
    }
    return result;
    }

    ReplyDelete
  7. Deepak KumarFebruary 14, 2020 at 7:30 AM

    public String repeatFront(String str, int n) {
    int len=str.length();
    String s="";
    for(n=n; n>=0; n--){

    s += str.substring(0,n);
    }
    return s;
    }

    ReplyDelete
  8. satyabratFebruary 22, 2020 at 7:37 PM

    public String repeatFront(String str, int n) {
    if(n==4)
    {
    str=str.substring(0,4)+str.substring(0,3)+str.substring(0,2)+str.substring(0,1);
    return str;
    }
    else if(n==3)
    {
    str=str.substring(0,3)+str.substring(0,2)+str.substring(0,1);
    return str;
    }
    else if(n==2)
    {
    return str.substring(0,2)+str.substring(0,1);
    }
    else if(n==0)
    {
    return "";
    }
    else if(n==1)
    {
    return str.substring(0,1);
    }
    return "";
    }

    ReplyDelete
  9. AtulApril 9, 2020 at 11:05 PM

    String str2="";
    for(int i=n;i>=0;i--)
    {
    str2+=str.substring(0,i);
    }
    return str2;

    ReplyDelete
  10. UnknownAugust 11, 2020 at 1:37 PM

    public String repeatFront(String str, int n) {
    if (n < 1)
    {
    return "";
    }
    else
    {
    return str.substring(0, n) + repeatFront(str.substring(0, n - 1), n - 1);
    }
    }

    ReplyDelete
  11. AnonymousSeptember 13, 2020 at 4:49 PM

    public String repeatFront(String str, int n) {
    if (n == 0 || str.isEmpty()){
    return "";
    }
    return str.substring(0, n) + repeatFront(str, n - 1);
    }

    ReplyDelete
  12. AnonymousSeptember 13, 2020 at 4:50 PM

    public String repeatFront(String str, int n) {
    return (n == 0 || str.isEmpty())? "":
    str.substring(0, n) + repeatFront(str, n - 1);
    }

    ReplyDelete
  13. UnknownSeptember 25, 2020 at 6:17 AM

    Kya boltay bantai log!!!

    ReplyDelete
  14. bkNovember 5, 2020 at 5:50 AM

    public String repeatFront(String str, int n) {
    String res="";
    while(n>0){
    res+=str.substring(0,n);
    n--;
    }
    return res;
    }

    ReplyDelete
  15. SinuserOctober 26, 2021 at 7:16 AM

    public String repeatFront(String str, int n)
    {
    String s = "";

    for(int i = 0; i < n; n--) s += str.substring(0 , n);

    return s;
    }

    ReplyDelete
  16. SardorbekDecember 3, 2021 at 3:30 AM

    bravo

    ReplyDelete
  17. SinuserDecember 31, 2021 at 6:23 PM

    public String repeatFront(String str, int n) {
    StringBuilder newStr = new StringBuilder();
    int count = n;

    for(int i = 0; i < n; i++){
    newStr.append(str.substring(0,count--));
    }

    return newStr.toString();
    }

    ReplyDelete
  18. UnknownFebruary 18, 2022 at 8:59 AM

    public String repeatFront(String str, int n) {
    String sum="";
    str=str.substring(0,n);
    for(int i=0; i<str.length(); i++){
    String temp=str.substring(0,str.length()-i);
    sum+=temp;
    }
    return sum;
    }

    ReplyDelete
  19. ShohimardonMarch 6, 2022 at 2:23 AM

    public String repeatFront(String str, int n) {
    String newstr = str.substring(0, n);
    int j = 0;
    String k = "";
    for (int i = newstr.length(); i >= 0; i--) {
    for (int l = i; l > 0; l--) {

    k += newstr.charAt(j);
    j++;
    }
    j = 0;
    }
    return k;
    }

    ReplyDelete