Java > String-2 > repeatEnd (CodingBat Solution)

Problem:

Given a string and an int N, return a string made of N repetitions of the last N characters of the string. You may assume that N is between 0 and the length of the string, inclusive.

repeatEnd("Hello", 3) → "llollollo"
repeatEnd("Hello", 2) → "lolo"
repeatEnd("Hello", 1) → "o"


Solution:

public String repeatEnd(String str, int n) {
  int len = str.length();
  String newWord = "";
  
  for (int i = 0; i < n; i++) {
    newWord += str.substring(len - n, len);
  }
  return newWord;
}

19 comments:

  1. AnonymousAugust 29, 2017 at 3:50 AM

    public String repeatEnd(String str, int n) {
    String result = "";

    for(int i=0; i<str.length() && i<n; i++)
    {
    result+= str.substring(str.length()-n);

    }


    return result;
    }

    ReplyDelete
  2. UnknownOctober 10, 2018 at 2:38 PM

    public String repeatEnd(String str, int n) {
    int len = str.length();
    String str1 = "";

    for (int i = 0; i < n ; i++)
    {
    str1 = str1+ str.substring(len-n, len);
    }
    return str1;
    }

    ReplyDelete
  3. Kamoliddin UsmonovMay 11, 2019 at 12:07 AM

    public String repeatEnd(String str, int n) {
    String needed = str.substring(str.length()-n);
    String result = "";
    for (int i = 0; i < n; i++) {
    result += needed;
    }
    return result;

    ReplyDelete
  4. DavidAugust 11, 2019 at 7:44 AM

    public String repeatEnd(String str, int n) {
    String s1="";
    String s2="";
    int size=n;
    for(int i=0;i<n;i++)
    {
    s1=s1+str.charAt(str.length()-size);
    size--;
    }
    for(int j=0;j<n;j++)
    {
    s2=s1+s2;
    }
    return s2;
    }

    ReplyDelete
  5. AbudéSeptember 1, 2019 at 11:47 PM

    public String repeatEnd(String str, int n) {
    String result = "";
    if ( n == 0 || n <= str.length() ){
    for ( int i = 0; i < n ; i++){
    result += str.substring(str.length() - n );
    }
    }
    return result;
    }

    ReplyDelete
  6. satyabratFebruary 22, 2020 at 6:59 PM

    public String repeatEnd(String str, int n) {
    String sol;
    if(n==0)
    {
    return "";
    }
    else if(n==3)
    {
    sol=str.substring(str.length()-3)+str.substring(str.length()-3)+
    str.substring(str.length()-3);
    return sol;
    }

    else if(n==2)
    {
    sol=str.substring(str.length()-2)+str.substring(str.length()-2);
    return sol;
    }
    return str.substring(str.length()-1);
    }

    ReplyDelete
  7. AtulApril 9, 2020 at 10:50 PM

    String str2="";
    for(int j=0;j<n;j++)
    {
    str2+=str.substring(str.length()-n,str.length());
    }
    return str2;

    ReplyDelete
  8. UnknownApril 12, 2020 at 2:39 AM

    public String repeatEnd(String str, int n) {
    String newWord = "";

    for(int i = 0; i < n; i++){
    newWord = newWord + str.substring(str.length()-n);
    }
    return newWord;
    }

    ReplyDelete
  9. UnknownMay 25, 2020 at 6:29 AM

    String d="";
    for(int i=0;i<n;i++){
    d+=str.substring(str.length()-n);
    }
    return d;
    }

    ReplyDelete
  10. AnonymousSeptember 13, 2020 at 4:46 PM

    public String repeatEnd(String str, int n) {
    if(n == 0 ){
    return "";
    }
    return new String(new char[n]).replace("\0", str.substring(str.length()-n));
    }

    ReplyDelete
  11. AnonymousSeptember 13, 2020 at 4:47 PM

    public String repeatEnd(String str, int n) {
    return (n == 0 )? ""
    :new String(new char[n]).replace("\0", str.substring(str.length()-n));
    }

    ReplyDelete
  12. AnarAghaSeptember 14, 2020 at 9:23 PM

    public String repeatEnd(String str, int n) {
    String blank = "";
    String tail = str.substring(str.length()-n);
    for(int i=0; i<n; i++){
    blank += tail;
    }
    return blank;

    }

    ReplyDelete
  13. UnknownSeptember 25, 2020 at 5:31 AM

    Laura lassoon pyaaz mirchi!


    public String repeatEnd(String str, int n) {
    String blank = "";
    String end = str.substring(str.length() - n);
    for(int i=0; i<n; i++){
    blank = blank + end;
    }return blank;
    }

    ReplyDelete
  14. UnknownOctober 5, 2020 at 7:56 AM

    public String repeatEnd(String str, int n) {
    String repeat = "";
    for (int i = 0; i < str.length(); i++) {
    if (i >= str.length() - n) {
    repeat = repeat + str.substring(str.length() - n);
    }
    }
    return repeat;
    }

    ReplyDelete
  15. GabeFebruary 18, 2021 at 3:45 PM

    public String repeatEnd(String str, int n) {

    String res = "";
    int len = str.length()-n;
    for(int i = 0; i < n; ++i) {

    res += str.substring(len);
    }

    return res;
    }

    ReplyDelete
  16. SinuserOctober 26, 2021 at 7:07 AM

    public String repeatEnd(String str, int n)
    {
    String s = "";

    for(int i = 0; i < n; i++)
    {
    s += str.substring(str.length()-n,str.length());
    }

    return s;
    }

    ReplyDelete
  17. AnonymousNovember 29, 2021 at 5:19 PM

    public String repeatEnd(String str, int n) {

    String result = "";
    int i = n;

    while(i != 0)
    {
    result += str.substring(str.length()-n, str.length());
    i--;
    }

    return result;
    }

    ReplyDelete
  18. Cema2009June 19, 2022 at 2:27 PM

    Another way

    public String repeatEnd(String str, int n) {
    return String.join("", Collections.nCopies(n, str.substring(str.length() - n)));
    }

    ReplyDelete