Java > String-2 > countCode (CodingBat Solution)

Problem:

Return the number of times that the string "code" appears anywhere in the given string, except we'll accept any letter for the 'd', so "cope" and "cooe" count.

countCode("aaacodebbb") → 1
countCode("codexxcode") → 2
countCode("cozexxcope") → 2


Solution:

public int countCode(String str) {
  int len = str.length();
  int count = 0;
  String co = "co";
  String e = "e";
  
  if (len < 4)
    return 0;
  
  for (int i = 0; i < len - 3; i++) {
    if (co.compareTo(str.substring(i,i+2)) == 0 && e.compareTo(str.substring(i+3, i+4)) == 0)
      count++;
  }
  return count;
}

25 comments:

  1. AnonymousDecember 2, 2015 at 6:10 AM

    public int countCode(String str)
    {
    int sum = 0;
    for (int i = 0; i < str.length()-3; ++i)
    {
    if (str.substring(i,i+2).equals("co") && str.charAt(i+3) == 'e') sum++;
    }
    return sum;
    }

    ReplyDelete
  2. VladimirJuly 25, 2017 at 3:43 PM

    Or using recursion...

    public int countCode(String str) {

    if (str.length() < 4)

    return 0;

    else if (str.charAt(0)=='c' && str.charAt(1)=='o' && str.charAt(3)=='e')

    return 1 + countCode(str.substring(4));

    else

    return countCode(str.substring(1));
    }

    ReplyDelete
  3. UnknownDecember 6, 2017 at 10:32 PM

    public int countCode(String str) {
    int c=0;
    for (int i=0; i < str.length()-3; i++)
    {
    if((str.substring(i,i+4).equals("code"))||str.substring(i,i+4).equals("cole")||str.substring(i,i+4).equals("cope")||str.substring(i,i+4).equals("coze")||str.substring(i,i+4).equals("core"))
    {
    c = ++c;
    }
    }
    return c;

    }

    ReplyDelete
  4. 3KMarch 16, 2018 at 4:54 PM

    public int countCode(String str) {
    int result = 0;
    for (int i = 0; i <= str.length()-4 ; i++) {
    if (str.substring(i,i+4).matches("co[a-z]e")) result++;
    }
    return result;
    }

    ReplyDelete
    Replies
    1. UnknownAugust 1, 2019 at 9:13 AM

      to take this a step more you can use \\w instead of [a-z]

      Delete
  5. UnknownOctober 3, 2018 at 12:57 PM

    public int countCode(String str) {
    int count = 0;
    for (int i = 0; i < str.length()-3; i++){
    if (str.substring(i).startsWith("co") && str.charAt(i+3) == 'e')
    count++;
    }
    return count;
    }

    ReplyDelete
  6. Cem UndenDecember 24, 2019 at 3:15 PM

    Recursion :

    public int countCode(String str) {

    if(str.length()<=3)
    return 0;

    if(str.charAt(0)=='c' && str.charAt(1)=='o' && str.charAt(3)=='e' )
    return 1+countCode(str.substring(4));
    return 0 + countCode(str.substring(1));

    }

    ReplyDelete
    Replies
    1. Cem UndenDecember 24, 2019 at 3:16 PM

      public int countCode(String str) {

      if(str.length()<=3)
      return 0;

      if(str.charAt(0)=='c' && str.charAt(1)=='o' && str.charAt(3)=='e' )
      return 1+countCode(str.substring(4));
      return 0 + countCode(str.substring(1));

      }

      Delete
  7. UnknownJuly 6, 2020 at 11:28 AM

    public int countCode(String str) {
    int countCode = 0;

    for (int i = 0; i < str.length() - 3; i++)
    {
    if (str.substring(i, i + 2).equals("co") && str.substring(i + 3, i + 4).equals("e"))
    {
    countCode++;
    }

    }

    return countCode;
    }

    ReplyDelete
  8. khushiAugust 7, 2020 at 5:59 PM


    int count = 0;

    for (int i=0; i<str.length()-3; i++) {
    if (str.substring(i, i+2).equals("co") && str.charAt(i+3) == 'e') {
    count++;
    }
    }
    return count;

    ReplyDelete
  9. UnknownAugust 20, 2020 at 12:00 PM

    public int countCode(String str) {
    int count = 0;
    for (int i = 0; i < str.length() - 3; i++) {
    if (str.substring(i,i+2).equals("co") && str.charAt(i+3) == 'e') {
    count++;
    i += 3;
    }
    }
    return count;
    }

    ReplyDelete
  10. AnarAghaSeptember 11, 2020 at 1:25 AM

    public int countCode(String str) {
    int count = 0;
    for (int i = 0; i < str.length(); i++) {
    if (str.substring(i).startsWith("co") && str.substring(i+3).startsWith("e")) {
    count++;
    }
    }
    return count;
    }

    ReplyDelete
  11. AnonymousSeptember 13, 2020 at 4:22 PM

    private final int countCode(String word) {
    if(word.length() <= 3){
    return 0;
    }
    if(word.charAt(0) == 'c'
    && word.charAt(1) == 'o'
    && word.charAt(3) == 'e'){
    return 1 + countCode(word.substring(4));
    }

    return countCode(word.substring(1));
    }

    ReplyDelete
  12. AnonymousSeptember 13, 2020 at 4:23 PM

    public int countCode(String str) {
    if(str.length() <= 3){
    return 0;
    }
    if(str.charAt(0) == 'c'
    && str.charAt(1) == 'o'
    && str.charAt(3) == 'e'){
    return 1 + countCode(str.substring(4));
    }
    return countCode(str.substring(1));
    }

    ReplyDelete
  13. AnonymousSeptember 13, 2020 at 4:25 PM

    public int countCode(String str) {
    if(str.length() <= 3){
    return 0;
    }
    return (str.charAt(0) == 'c'
    && str.charAt(1) == 'o'
    && str.charAt(3) == 'e')? (1 + countCode(str.substring(4))):countCode(str.substring(1));
    }

    ReplyDelete
  14. AnonymousSeptember 13, 2020 at 4:26 PM

    public int countCode(String str) {
    if(str.length() <= 3){
    return 0;
    }
    return (str.charAt(0) == 'c'
    && str.charAt(1) == 'o'
    && str.charAt(3) == 'e')?
    (1 + countCode(str.substring(4))):
    countCode(str.substring(1));
    }

    ReplyDelete
  15. AnonymousSeptember 18, 2020 at 5:27 AM

    public int countCode(String str) {
    return (str.length() <= 3)? 0:
    (str.charAt(0) == 'c' && str.charAt(1) == 'o' && str.charAt(3) == 'e')?
    1 + countCode(str.substring(4)) : countCode(str.substring(1));
    }
    }

    ReplyDelete
  16. AnonymousSeptember 18, 2020 at 5:28 AM

    public int countCode(String str) {
    return (str.length() <= 3)? 0:
    (str.charAt(0) == 'c' && str.charAt(1) == 'o' && str.charAt(3) == 'e')?
    1 + countCode(str.substring(4)) : countCode(str.substring(1));
    }

    ReplyDelete
  17. Anmol ParikhJanuary 12, 2021 at 11:10 AM

    public int countCode(String str) {
    int count=0;
    for(int i=0;i<str.length()-3;i++){
    if((str.substring(i,i+4).equals("code"))||((str.substring(i,i+2).equals("co"))&&str.substring(i+3,i+4).equals("e")))
    count++;
    }
    return count;
    }

    ReplyDelete
  18. Anmol ParikhJanuary 12, 2021 at 11:13 AM

    public int countCode(String str) {
    int count=0;
    for(int i=0;i<str.length()-3;i++){
    if(str.substring(i,i+4).matches("co[a-z]e"))
    count++;
    }
    return count;
    }

    ReplyDelete
  19. Anmol ParikhMarch 12, 2021 at 6:41 AM

    public int countCode(String str) {
    int count=0;
    for(int i=0;i<str.length()-3;i++){
    if((str.substring(i,i+2).equals("co"))&&(str.substring(i+3,i+4).equals("e"))){
    count++;
    }
    }return count;
    }

    ReplyDelete
  20. UnknownJune 19, 2021 at 8:07 AM

    public int countCode(String str)
    {
    int count=0;
    if(str.length()<2)
    {
    return count ;
    }
    else
    {
    for(int i=0;i<=str.length()-4;i++)
    {
    if(str.charAt(i)=='c' && str.charAt(i+1)=='o' && str.charAt(i+3)=='e')
    {
    count++;
    }
    else
    {
    count=count;
    }
    }
    }
    return count;

    }

    ReplyDelete
  21. smokemachineJanuary 10, 2022 at 4:03 AM

    int cont = 0;
    for (int i=0; i<str.length()-3;i++){
    if (str.substring(i,i+2).equals("co") && (str.substring(i+3,i+4).equals("e"))){
    cont ++;
    }
    }
    return cont;

    ReplyDelete
  22. Cema2009June 18, 2022 at 7:41 PM

    Another way

    public int countCode(String str) {
    return str.split("co\\we", - 1).length - 1;
    }

    ReplyDelete
  23. Sherzod Nurboev from PDP academyJanuary 25, 2024 at 12:19 PM

    public int countCode(String str) {
    int code=0;
    for(int i=0; i<str.length()-3;i++){
    if(str.charAt(i)=='c'&&str.charAt(i+1)=='o'&&str.charAt(i+3)=='e')
    code++;
    }return code;
    }

    ReplyDelete