Java > String-1 > without2 (CodingBat Solution)

Problem:

Given a string, if a length 2 substring appears at both its beginning and end, return a string without the substring at the beginning, so "HelloHe" yields "lloHe". The substring may overlap with itself, so "Hi" yields "". Otherwise, return the original string unchanged.

without2("HelloHe") → "lloHe"
without2("HelloHi") → "HelloHi"
without2("Hi") → ""


Solution:

public String without2(String str) {
  int len = str.length();
  if (len == 2)
    return "";
  if (len < 2)
    return str;
  else {
    if (str.substring(0,2).equals(str.substring(len-2, len)))
      return str.substring(2,len);
      else return str;
  
  } 
}

9 comments:

  1. UnknownApril 6, 2018 at 12:27 PM

    public String without2(String str) {

    if(str.length()>1 && str.substring(0,2).equals(str.substring(str.length()-2)))
    return str.substring(2,str.length());
    else return str;
    }

    ReplyDelete
    Replies
    1. BusterOctober 25, 2018 at 6:43 AM

      this one actually worked for me, the suggested solution in the main post didn't :) thanks!

      Delete
  2. UnknownOctober 11, 2018 at 8:44 PM

    public String without2(String str) {
    int x = str.length();

    if(x == 1)
    {
    return str;
    }
    else if(x <= 2)
    {
    return "";
    }
    else if(str.substring(0,2).equals(str.substring(x-2,x)))
    {
    return str.substring(2,x);
    }
    else
    {
    return str;
    }
    }

    ReplyDelete
  3. KnownJune 13, 2019 at 3:17 AM

    public String without2(String str) {
    if(str.length() >= 2) {
    String front = str.substring(0, 2), back = str.substring(str.length() - 2);
    if(front.equals(back)) return str.substring(2);
    }
    return str;
    }

    ReplyDelete
  4. UnknownMay 10, 2020 at 6:29 PM

    public String without2(String str) {
    return str.length() > 1 && str.substring(0,2).equals(str.substring(str.length()-2)) ? str.substring(2, str.length()):str;

    }

    ReplyDelete
  5. Anmol ParikhJanuary 11, 2021 at 9:01 PM

    public String without2(String str) {
    if(str.length()>3){
    String a=str.substring(0,2);
    String b=str.substring(str.length()-2,str.length());
    String c=str.substring(2,str.length()-2);
    if(a.equals(b)){
    return c+a;
    }
    }if(str.length()==2){
    return "";
    }
    if(str.length()==3 && ((str.substring(0,1)).equals(str.substring(str.length()-1,str.length())))){
    return (str.substring(1,str.length()-1));
    }
    else return str;

    }

    ReplyDelete
  6. ewedaaNovember 13, 2021 at 1:43 PM

    public String without2(String str) {
    if(str.length()>1 && str.substring(0,2).equals(str.substring(str.length()-2)))
    return str.substring(2);
    else return str;
    }

    ReplyDelete
  7. AvengerDecember 9, 2021 at 8:32 AM

    public String without2(String str)
    {
    int len = 2;
    if(str.length()<2)
    len = str.length();

    String data = str;

    if(str.endsWith(str.substring(0,len)) && str.length() > 1)
    data = str.substring(len);

    return data;
    }

    ReplyDelete
  8. UnknownMarch 31, 2022 at 5:46 AM

    public String without2(String str) {
    int len = str.length();

    if (len == 2)
    {
    return "";
    }
    else if (len <= 1)
    {
    return str;
    }
    else if ( str.substring(0,2).equals( str.substring(len-2, len) ) )
    {
    return str.substring( 2,len );
    }

    return str;

    }

    Removed the extra bracket.

    ReplyDelete