Java > String-1 > theEnd (CodingBat Solution)

Problem:

Given a string, return a string length 1 from its front, unless front is false, in which case return a string length 1 from its back. The string will be non-empty.

theEnd("Hello", true) → "H"
theEnd("Hello", false) → "o"
theEnd("oh", true) → "o"


Solution:

public String theEnd(String str, boolean front) {
  if (front)
    return str.substring(0,1);
  else
    return str.substring(str.length()-1);
}

4 comments:

  1. AnonymousSeptember 13, 2020 at 2:36 PM

    public String theEnd(String str, boolean front) {
    if(front){
    return String.valueOf(str.charAt(0));
    }
    return String.valueOf(str.charAt(str.length() - 1));
    }

    ReplyDelete
  2. AnonymousSeptember 13, 2020 at 2:36 PM

    public String theEnd(String str, boolean front) {
    if(front){
    return String.valueOf(str.charAt(0));
    }
    return String.valueOf(str.charAt(str.length() - 1));
    }

    ReplyDelete
  3. AnonymousSeptember 13, 2020 at 2:36 PM

    public String theEnd(String str, boolean front) {
    if(front){
    return String.valueOf(str.charAt(0));
    }
    return String.valueOf(str.charAt(str.length() - 1));
    }

    ReplyDelete
  4. UnknownSeptember 27, 2020 at 2:23 AM

    public String theEnd(String str, boolean front) {
    int leng = str.length();
    return (front == true) ? str.substring(0,1) : str.substring(leng-1,leng);
    }

    ReplyDelete