Java > String-1 > nTwice (CodingBat Solution)

Problem:

Given a string and an int n, return a string made of the first and last n chars from the string. The string length will be at least n.

nTwice("Hello", 2) → "Helo"
nTwice("Chocolate", 3) → "Choate"
nTwice("Chocolate", 1) → "Ce"


Solution:

public String nTwice(String str, int n) {
  return str.substring(0,n) + str.substring(str.length()- n, str.length());
}

4 comments:

  1. AnonymousMay 6, 2019 at 8:16 AM

    public String nTwice(String str, int n) {
    return str.substring(0,n).concat(str.substring(str.length()-n));
    }

    ReplyDelete
  2. Anmol ParikhJanuary 10, 2021 at 11:34 AM

    public String nTwice(String str, int n) {
    String a=str.substring(0,n);
    String b=str.substring(str.length()-n);
    return a+b;
    }

    ReplyDelete
  3. UnknownFebruary 28, 2021 at 4:28 AM

    public String nTwice(String str, int n) {
    String res="";
    String fst=str.substring(0,n);
    String lst=str.substring(str.length()-n,str.length());
    return res=fst+lst;
    }

    ReplyDelete
  4. UnknownJune 19, 2021 at 7:14 AM

    public String nTwice(String str, int n) {
    if(str=="")
    {
    return str;
    }
    else
    {
    int ub=str.length()-1;
    return str.substring(0,n) + str.substring(ub-n+1,str.length());
    }
    }

    ReplyDelete