Java > String-1 > extraEnd (CodingBat Solution)

Problem:

Given a string, return a new string made of 3 copies of the last 2 chars of the original string. The string length will be at least 2.

extraEnd("Hello") → "lololo"
extraEnd("ab") → "ababab"
extraEnd("Hi") → "HiHiHi"


Solution:

public String extraEnd(String str) {
  String s = str.substring(str.length()-2, str.length());
  return s+s+s;
}

6 comments:

  1. ChithiraiDecember 23, 2018 at 6:12 AM

    public String extraEnd(String str) {
    if(str.length()<2)
    {
    return str;
    }
    String end = str.substring(str.length()-2,str.length());
    return end+end+end;
    }

    ReplyDelete
  2. AnonymousSeptember 13, 2020 at 2:48 PM

    public String extraEnd(String str) {
    final String lastTwo = "" + str.charAt(str.length() - 2) + str.charAt(str.length() - 1);
    return lastTwo + lastTwo + lastTwo ;
    }

    ReplyDelete
  3. UnknownFebruary 28, 2021 at 4:09 AM

    public String extraEnd(String str) {
    String res="";
    String m=str.substring(str.length()-2,str.length());
    if(str.length()==2)
    return res=str+str+str;
    else
    return res=m+m+m;
    }

    ReplyDelete
  4. UnknownApril 24, 2021 at 7:55 AM

    public String extraEnd(String str) {
    String penultimate = str.substring(str.length() - 2);
    String last = str.substring(str.length());
    String sumReiteration = penultimate + last;
    return sumReiteration + sumReiteration + sumReiteration;
    }

    ReplyDelete
  5. UnknownJune 19, 2021 at 7:02 AM

    public String extraEnd(String str) {
    if(str.length()-1<1)
    {
    return str + str + str;
    }
    else
    {
    String newstr=str.substring(str.length()-2,str.length());
    return newstr + newstr + newstr;
    }
    }

    ReplyDelete
  6. unknownJune 2, 2023 at 12:16 PM

    public String extraEnd(String str) {
    String ans ;
    int s2 = str.length();
    String s1 = str.substring(s2-2,s2);
    ans = s1+s1+s1;
    return ans;
    }

    ReplyDelete