Java > String-1 > atFirst (CodingBat Solution)

Problem:

Given a string, return a string length 2 made of its first 2 chars. If the string length is less than 2, use '@' for the missing chars.

atFirst("hello") → "he"
atFirst("hi") → "hi"
atFirst("h") → "h@"


Solution:

public String atFirst(String str) {
  if (str.length() >= 2)
    return str.substring(0,2);
  else if (str.length() == 1)
    return str + "@";
  else
    return "@@";
}

7 comments:

  1. AnonymousJanuary 22, 2017 at 8:21 AM

    public String atFirst(String str) {

    if(str.equals(""))
    return str + "@" +"@";

    if(str.length()<2)
    return str +"@";

    String s = str.substring(0,2);
    return s;
    }

    ReplyDelete
  2. ChithiraiDecember 23, 2018 at 5:43 AM

    public String atFirst(String str) {
    if(str.length()==0)
    {
    return "@@";
    }
    if(str.length()<2)
    {
    return str+"@";
    }
    return str.substring(0,2);

    }

    ReplyDelete
  3. UnknownMay 9, 2020 at 12:50 AM

    public String atFirst(String str) {
    return str.length()>=2?str.substring(0,2):str.length()==1?str+"@":str+"@@";
    }

    ReplyDelete
  4. AnonymousSeptember 13, 2020 at 3:33 PM

    public String atFirst(String str) {
    if(str.isEmpty()){
    return "@@";
    }
    if(str.length() == 1){
    return str + '@';
    }
    return "" + str.charAt(0) + str.charAt(1);
    }

    ReplyDelete
  5. UnknownNovember 3, 2020 at 12:27 AM

    “TUIT” -> “UI”
    sorry

    ReplyDelete
  6. Anmol ParikhJanuary 11, 2021 at 9:55 AM

    public String atFirst(String str) {
    String a="@";
    if(str.length()>=2){
    return str.substring(0,2);
    }
    if(str.length()<2 && str.length()>0){
    return str.substring(0).concat("@");
    }
    if(str.isEmpty()){
    return a+a;
    }return str;
    }

    ReplyDelete
  7. asahiJuly 27, 2021 at 7:20 AM

    public String lastChars(String a, String b) {
    String first = "";
    first = a.length()< 1 ? "@" : a.substring(0,1);
    String last = "";
    last = b.length()< 2 ? "@" : b.substring(b.length() -1, b.length());
    return first + last;

    }

    ReplyDelete