Java > Array-2 > fizzArray3 (CodingBat Solution)

Problem:

Given start and end numbers, return a new array containing the sequence of integers from start up to but not including end, so start=5 and end=10 yields {5, 6, 7, 8, 9}. The end number will be greater or equal to the start number. Note that a length-0 array is valid. (See also: FizzBuzz Code)

fizzArray3(5, 10) → {5, 6, 7, 8, 9}
fizzArray3(11, 18) → {11, 12, 13, 14, 15, 16, 17}
fizzArray3(1, 3) → {1, 2}


Solution:

public int[] fizzArray3(int start, int end) {
    int n = end - start;
    int[] result = new int[n];
 
    for (int i = 0; i < n; i++)
        result[i] = start++;
    return result;
}

13 comments:

  1. UnknownMarch 2, 2017 at 8:54 AM


    int dif = end-start;
    int[] erg = new int[dif];

    for(int i=0; i < dif; i++){
    erg[i] = start+i;
    }
    return erg;

    ReplyDelete
  2. UnknownApril 4, 2018 at 8:02 PM

    public int[] fizzArray3(int start, int end) {
    int[] newArray = new int[end-start];
    int count = 0;
    for(int i=start; i<end; i++){
    newArray[count] = i;
    count++;
    }
    return newArray;
    }

    ReplyDelete
  3. UnknownOctober 13, 2018 at 10:46 AM

    public int[] fizzArray3(int start, int end) {
    int[] arr = new int[end-start];
    for (int i=start; i<end; i++){
    //if (i==start)
    arr[i-start]=i;
    }
    return arr;
    }

    ReplyDelete
  4. fergcodyJanuary 7, 2019 at 11:59 AM

    public int[] fizzArray3(int start, int end) {
    int[] newArray = new int[end - start];
    int addOn = 0;

    for(int i = 0; i < end - start; i++) {
    newArray[i] = start + addOn;
    addOn++;
    }
    return newArray;
    }

    ReplyDelete
  5. IntercisaJune 17, 2019 at 7:34 AM

    public int[] fizzArray3(int start, int end) {

    int[] fizzArray = new int[end - start];

    for (int i = 0, j = start; j < end; i++, j++) {

    fizzArray[i] = j;
    }
    return fizzArray;

    ReplyDelete
  6. KnownJune 23, 2019 at 4:40 AM

    public int[] fizzArray3(int start, int end) {
    if(start >= end) return new int[0];

    int[] out = new int[end - start];
    for(int i = 0; i < out.length; i++) {
    out[i] = start + i;
    }
    return out;
    }

    ReplyDelete
  7. ygguguFebruary 26, 2020 at 1:59 AM

    public int[] fizzArray3(int start, int end) {
    int[] q=new int[end-start];
    int a=end-start;
    for(int i=0;i<a;i++){
    q[i]=start++;
    }return q;
    }

    ReplyDelete
  8. Gouthami KothakapuApril 9, 2020 at 10:09 PM

    public int[] fizzArray3(int start, int end) {
    int diff = end-start;
    int[] result = new int[diff];
    for(int i=0; i<diff; i++)
    {
    result[i] = start;
    start++;
    }return result;
    }

    ReplyDelete
  9. DIVRITMay 20, 2020 at 12:18 AM

    public int[] fizzArray3(int start, int end) {
    int size=end-start;
    int a[]=new int[(size)];

    for(int i=0;i<size;i++){
    a[i]=start++;
    }
    return a;
    }

    ReplyDelete
  10. LKayaJanuary 21, 2022 at 12:18 PM

    int len= end-start;

    int [] newArray= new int [len];

    for (int i=0; i<len ; i++){
    newArray [i] = start+i;
    }

    return newArray;

    ReplyDelete
  11. Cema2009June 7, 2022 at 7:40 PM

    With Java Stream

    public int[] fizzArray3(int start, int end) {
    return java.util.stream.IntStream.range(start, end).toArray();
    }

    ReplyDelete
  12. pdpJavaG8July 5, 2022 at 12:33 AM

    public int[] fizzArray3(int start, int end) {
    int s = end - start;
    int[] nums = new int[s];

    for(int i = start,j=0; i < end; i++,j++){
    nums[j] += i;
    }
    return nums;
    }

    ReplyDelete
  13. nuurJuly 17, 2022 at 9:30 PM

    public int[] fizzArray3(int start, int end) {

    int[] b=new int[end-start];
    for(int i=start,j=0;i<end;i++,j++){
    b[j]=i;
    }
    return b;

    }

    ReplyDelete