Java > Array-2 > fizzArray2 (CodingBat Solution)

Problem:

Given a number n, create and return a new string array of length n, containing the strings "0", "1" "2" .. through n-1. N may be 0, in which case just return a length 0 array. Note: String.valueOf(xxx) will make the String form of most types. The syntax to make a new string array is: new String[desired_length] (See also: FizzBuzz Code)

fizzArray2(4) → {"0", "1", "2", "3"}
fizzArray2(10) → {"0", "1", "2", "3", "4", "5", "6", "7", "8", "9"}
fizzArray2(2) → {"0", "1"}


Solution:

public String[] fizzArray2(int n) {
    String[] result = new String[n];
    for (int i = 0; i < n; i++)
        result[i] = String.valueOf(i);
    return result;
}

11 comments:

  1. UnknownApril 27, 2019 at 1:06 PM

    public String[] fizzArray2(int n) {
    String[] result = new String[n];
    for(int i = 0; i < n; i++)
    {
    result[i] = String.valueOf(i);
    }
    return result;
    }

    ReplyDelete
  2. AnonymousMay 27, 2019 at 5:46 AM

    ```
    public String[] fizzArray2(int n) {
    return java.util.stream.IntStream.range(0, n)
    .boxed().map(String::valueOf).toArray(String[]::new);
    }
    ```

    ReplyDelete
  3. KennyFebruary 7, 2020 at 11:31 AM

    public String[] fizzArray2(int n) {

    String[] out = new String[n];
    int c = 0;

    for(int i = 0; i < n; i++){
    out[i] = Integer.toString(c++);
    } return out;
    }

    ReplyDelete
  4. LearningCodingApril 10, 2020 at 10:18 PM

    public String[] fizzArray2(int n) {
    String[] s = new String[n];

    for(int i=0;i<n;i++) {
    s[i] = new Integer(i).toString();
    }

    return s;
    }

    ReplyDelete
  5. AnonymousSeptember 21, 2020 at 4:18 AM

    public String[] fizzArray2(int n) {
    String[] strArray = new String[n];
    Arrays.setAll(strArray, String::valueOf);
    return strArray;
    }

    ReplyDelete
  6. AnonymousSeptember 21, 2020 at 4:25 AM

    public String[] fizzArray2(int n) {
    String[] strArray = new String[n];
    Arrays.setAll(strArray, String::valueOf);
    return strArray;
    }

    ReplyDelete
  7. AnonymousSeptember 21, 2020 at 4:25 AM

    public String[] fizzArray2(int n) {
    String[] strArray = new String[n];
    Arrays.setAll(strArray, String::valueOf);
    return strArray;
    }

    ReplyDelete
  8. UnknownJuly 14, 2021 at 10:28 PM

    public String[] fizzArray2(int n) {
    String re[]=new String[n];
    for(int i=0;i<n;i++)
    {
    re[i]=""+i+"";
    }
    return re;
    }

    ReplyDelete
  9. SinuserOctober 28, 2021 at 7:44 AM

    public String[] fizzArray2(int n)
    {
    String[] newArray = new String[n];

    for(int i = 0; i < n; i++)
    {
    newArray[i] = String.valueOf(i);
    }

    return (newArray);
    }

    ReplyDelete
  10. Cema2009June 6, 2022 at 5:28 PM


    with Java Stream

    public static String[] fizzArray2(int n) {

    int[] arr = IntStream.range(0, n).toArray();

    return Arrays.stream(arr)
    .mapToObj(String::valueOf)
    .toArray(String[]::new);

    }

    ReplyDelete
  11. nuurJuly 14, 2022 at 9:46 PM

    public String[] fizzArray2(int n) {
    String[] a=new String[n];
    for(int i=0;i<n;i++)

    a[i]=(""+i+"");


    return a;
    }

    ReplyDelete