Java > Array-2 > either24 (CodingBat Solution)

Problem:

Given an array of ints, return true if the array contains a 2 next to a 2 or a 4 next to a 4, but not both.

either24({1, 2, 2}) → true
either24({4, 4, 1}) → true
either24({4, 4, 1, 2, 2}) → false


Solution:

public boolean either24(int[] nums) {
  boolean found2 = false;
  boolean found4 = false;
  
  for (int i = 0;i < nums.length; i++) {
    if (nums[i] == 2 && i < nums.length-1 && nums.length > 1 && nums[i+1] == 2)
      found2 = true;
    if (nums[i] == 4 && i < nums.length-1 && nums.length > 1 && nums[i+1] == 4)
      found4 = true;
  }
  
  if (found2 && found4)
    return false;
  else if (!found2 && !found4)
    return false;
  else
    return true;
  
}

17 comments:

  1. AnonymousJanuary 28, 2015 at 11:37 AM

    public boolean either24(int[] nums) {
    boolean esta = false;
    boolean dos = false;
    boolean cuatro = false;

    for(int i=0; i<nums.length-1; i++)
    {

    if(nums[i]==4 && nums[i+1]==4)
    {
    esta = true;
    cuatro=true;
    }

    if(nums[i]==2 && nums[i+1]==2)
    {
    esta = true;
    dos=true;
    }

    if(dos && cuatro)
    {
    esta = false;
    break;
    }
    }

    return esta;
    }

    ReplyDelete
  2. AnonymousJune 15, 2016 at 12:03 PM

    public boolean either24(int[] nums) {
    boolean fours=false;
    boolean twos=false;

    for(int i=0;i<=nums.length-2;i++){
    if(nums[i]==2 && nums[i+1]==2){
    twos=true;
    }

    else if(nums[i]==4 && nums[i+1]==4){
    fours=true;
    }


    }

    if(fours && twos){
    return false;
    }
    if(!fours && !twos){
    return false;
    }

    else return true;

    }

    ReplyDelete
  3. MichałDecember 16, 2016 at 11:53 AM

    I think that my solution is easier..
    public boolean either24(int[] nums) {
    boolean war2 = false;
    boolean war4 = false;

    for (int i = 0; i < nums.length-1; i++)
    {
    if (nums[i] == 2 && nums[i+1] == 2)
    war2 = true;
    if (nums[i] == 4 && nums[i+1] == 4)
    war4 = true;
    }
    if (war2 == war4)
    return false;
    else
    return true;
    }

    ReplyDelete
  4. UnknownDecember 30, 2016 at 4:01 PM

    A better Version :
    public boolean either24(int[] nums) {
    boolean zwei =false;
    boolean vier = false;
    for(int i =0; i<nums.length - 1; i++){

    if(nums[i]== 2 && nums[i + 1]==2){
    zwei =true;
    }
    if(nums[i]== 4 && nums[i + 1]== 4){
    vier =true;
    }

    }
    if(vier==true ^ zwei == true){
    return true;
    }


    return false;

    }

    ReplyDelete
  5. AnonymousMarch 5, 2017 at 2:41 PM

    public boolean either24(int[] nums) {

    boolean two = false;
    boolean four = false;

    for(int i = 0; i < nums.length-1; i++) {

    if (nums[i] == 2 && nums[i+1] == 2) two = true;
    if (nums[i] == 4 && nums[i+1] == 4) four = true;

    }return two ^ four;

    }

    ReplyDelete
  6. UnknownSeptember 8, 2018 at 10:44 PM

    if(Arrays.toString(nums).contains("2, 2")&&Arrays.toString(nums).contains("4, 4"))
    return false;
    if(Arrays.toString(nums).contains("2, 2")||Arrays.toString(nums).contains("4, 4"))
    return true;
    return false;

    ReplyDelete
  7. UnknownNovember 3, 2018 at 5:12 PM

    public boolean either24(int[] nums) {
    boolean twotwo=false;
    boolean fourfour= false;
    for(int i = 0;i<nums.length -1;i++){
    if (nums[i]==2 && nums[i+1]==2){
    twotwo=true;
    }
    if (nums[i]==4 && nums[i+1] ==4){
    fourfour = true;
    }
    }
    if( twotwo && fourfour) {
    return false;
    }
    return (twotwo || fourfour);
    }

    ReplyDelete
  8. cherokee_roseJune 18, 2019 at 4:17 AM

    String arrS = Arrays.toString(nums).replaceAll("\\[|,|\\]|\\s","");
    boolean isTrue =
    (arrS.contains("22")&&!arrS.contains("44"))?true:
    (arrS.contains("44")&&!arrS.contains("22"))?true:false;
    return isTrue;

    ReplyDelete
  9. CodinWhizJanuary 24, 2020 at 12:23 PM

    int c2=0,c4=0;
    for(int i=0;i0 && c4==0) || (c4>0 && c2==0);

    ReplyDelete
    Replies
    1. CodinWhizJanuary 24, 2020 at 12:23 PM

      int c2=0,c4=0;
      for(int i=0;i0 && c4==0) || (c4>0 && c2==0);

      Delete
  10. CodinWhizJanuary 24, 2020 at 12:28 PM

    doesn't let me to share whole code(?)

    ReplyDelete
  11. LearningCodingApril 12, 2020 at 4:08 PM

    public boolean either24(int[] nums) {
    int four =0;
    int two= 0;
    for(int i=0; i0 && two==0) {
    return true;
    }

    else if(two>0 && four==0) {
    return true;
    }

    else{
    return false;
    }
    }

    ReplyDelete
  12. LearningCodingApril 12, 2020 at 4:09 PM

    public boolean either24(int[] nums) {
    int four =0;
    int two= 0;
    for(int i=0; i0 && two==0) {
    return true;
    }

    else if(two>0 && four==0) {
    return true;
    }

    else{
    return false;
    }
    }

    ReplyDelete
  13. AnonymousSeptember 21, 2020 at 4:27 AM

    public boolean either24(int[] nums) {
    if (Arrays.toString(nums).contains("2, 2")) {
    if (Arrays.toString(nums).contains("4, 4")) {
    return false;
    }
    }
    return Arrays.toString(nums).contains("2, 2")
    || Arrays.toString(nums).contains("4, 4");
    }

    ReplyDelete
  14. AnonymousSeptember 30, 2020 at 4:02 AM

    public boolean either24(int[] nums) {
    return Arrays.toString(nums).contains("2, 2") != Arrays.toString(nums).contains("4, 4");
    }

    ReplyDelete
  15. AnonymousSeptember 30, 2020 at 4:02 AM

    public boolean either24(int[] nums) {
    return Arrays.toString(nums).contains("2, 2") != Arrays.toString(nums).contains("4, 4");
    }

    ReplyDelete
  16. UnknownFebruary 26, 2022 at 4:50 PM

    public boolean either24(int[] nums) {
    boolean is2 = false;
    boolean is4 = false;

    for(int i = 0; i<nums.length-1;i++){
    if(nums[i]==2 && nums[i+1]==2){
    is2 = true;
    }
    else if(nums[i]==4 && nums[i+1]==4){
    is4 = true;
    }
    }

    if(is2 && is4){
    return false;
    }else if( !is2 & !is4){
    return false;
    }else {
    return true;
    }

    }

    ReplyDelete