Java > Array-1 > front11 (CodingBat Solution)

Problem:

Given 2 int arrays, a and b, of any length, return a new array with the first element of each array. If either array is length 0, ignore that array.

front11({1, 2, 3}, {7, 9, 8}) → {1, 7}
front11({1}, {2}) → {1, 2}
front11({1, 7}, {}) → {1}


Solution:

public int[] front11(int[] a, int[] b) {
  if (a.length == 0 && b.length == 0) {
    return a;
  }
  if (a.length == 0) {
    int[] myArray = new int[] {b[0]};
    return myArray;
  }
  
  if (b.length == 0) {
    int[] myArray = new int[] {a[0]};
    return myArray;
  }
  
  int[] myArray = new int[] {a[0], b[0]};
  return myArray;    
}

7 comments:

  1. mccarthypaul11August 20, 2017 at 2:39 PM

    public int[] front11(int[] a, int[] b) {
    int []c =new int[0];

    if(a.length>0 && b.length>0){
    c = new int[2];
    c[0]=a[0];
    c[1]=b[0];
    }else if( a.length == 0 && b.length>1){
    c = new int[1];
    c[0]=b[0];
    }else if(b.length == 0 && a.length>1){
    c = new int[1];
    c[0]=a[0];
    }
    return c;

    }

    ReplyDelete
  2. AnonymousSeptember 19, 2020 at 4:19 PM

    public int[] front11(int[] a, int[] b) {
    if(a.length == 0 && b.length == 0){
    return new int[]{};
    }
    if(a.length == 0){
    return new int[]{b[0]};
    }
    if(b.length == 0){
    return new int[]{a[0]};
    }
    return new int[]{a[0], b[0]};
    }

    ReplyDelete
  3. Anmol ParikhJanuary 15, 2021 at 3:34 AM

    public int[] front11(int[] a, int[] b) {
    int[] arr=new int[2];
    int[] ar1=new int[1];
    int[] ar2=new int[0];
    int aLen=a.length;
    int bLen=b.length;
    if(aLen==0 && bLen==1){
    arr[0]=b[0];
    return arr;
    }
    if((aLen==1 && bLen==0) || (aLen>1 && bLen==0)){
    ar1[0]=a[0];
    return ar1;
    }
    if((aLen==0 && bLen==0)){
    return ar2;
    }
    if((aLen==0 && bLen==1) || (aLen==0 && bLen>0)){
    ar1[0]=b[0];
    return ar1;
    }
    if((aLen>2 && bLen>0)||(aLen==1 && bLen==1)||(aLen==1 && bLen>1)){
    arr[0]=a[0];
    arr[1]=b[0];
    return arr;
    } return a;
    }

    ReplyDelete
  4. RajeshApril 22, 2021 at 3:58 AM

    public int[] front11(int[] a, int[] b) {
    if(a.length>=1 && b.length>=1)
    return new int[] {a[0],b[0]};
    else if (a.length>=1 && !(b.length>=1))
    return new int [] {a[0]};
    else if (!(a.length>=1) && b.length>=1)
    return new int [] {b[0]};
    else return a;
    }

    ReplyDelete
  5. UnknownOctober 27, 2021 at 1:05 PM

    public int[] front11(int[] a, int[] b) {
    if(a.length!=0&&b.length!=0) return new int[] {a[0],b[0]};
    if(a.length==0&&b.length==0)return new int[] {};
    if(a.length==0) return new int[] { b[0]};
    else return new int[] {a[0]};
    }

    ReplyDelete
  6. yogeshMarch 19, 2022 at 9:33 AM

    public int[] front11(int[] a, int[] b) {
    if(a.length==0 && b.length==0)
    return a;
    else if(a.length!=0 && b.length!=0)
    {
    int t[]={a[0],b[0]};
    return t;
    }
    else if(a.length==0)
    {
    int t[]={b[0]};
    return t;
    }

    int t[]={a[0]};
    return t;
    }

    ReplyDelete
  7. Java & meJune 20, 2022 at 11:02 AM

    public int[] front11(int[] a, int[] b) {
    return ((a.length>0)&&(b.length>0))? new int [] {a[0],b[0]} :
    (a.length>0)? new int [] {a[0]} : (b.length>0)? new int [] {b[0]}:
    new int []{};
    }

    ReplyDelete