Java > AP-1 > wordsCount (CodingBat Solution)

Problem:

Given an array of strings, return the count of the number of strings with the given length.

wordsCount({"a", "bb", "b", "ccc"}, 1) → 2
wordsCount({"a", "bb", "b", "ccc"}, 3) → 1
wordsCount({"a", "bb", "b", "ccc"}, 4) → 0


Solution:

public int wordsCount(String[] words, int len) {
  int count = 0;  
  for (int i = 0; i < words.length; i++) {
    if (words[i].length() == len)
      count++;
  }
  return count;
}

4 comments:

  1. AnonymousFebruary 16, 2018 at 4:25 AM

    int count=0;
    for(String w : words){
    if(w.length()==len) count++;
    }
    return count;

    ReplyDelete
  2. AnonymousSeptember 20, 2020 at 3:25 AM

    public int wordsCount(String[] words, int len) {
    int count = 0;
    for (final String word : words) {
    if (word.length() == len) {
    count++;
    }
    }
    return count;
    }

    ReplyDelete
  3. AbhishekAugust 16, 2021 at 12:29 AM

    public int wordsCount(String[] words, int len) {
    int c=0;
    for(int i=0;i<words.length;i++)
    if(words[i].length()==len)
    c++;
    return c;
    }

    ReplyDelete
  4. SinuserOctober 28, 2021 at 9:56 AM

    public int wordsCount(String[] words, int len)
    {
    int counter = 0;

    for(int i = 0; i < words.length; i++)
    {
    if(words[i].length() == len) counter++;
    }

    return counter;
    }

    ReplyDelete